-16t^2=96t+60

Solution for -16t^2=96t+60 equation:

-16t^2=96t+60

We move all terms to the left:

-16t^2-(96t+60)=0

We get rid of parentheses

-16t^2-96t-60=0

a = -16; b = -96; c = -60;
Δ = b2-4ac
Δ = -962-4·(-16)·(-60)
Δ = 5376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5376}=\sqrt{256*21}=\sqrt{256}*\sqrt{21}=16\sqrt{21}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-96)-16\sqrt{21}}{2*-16}=\frac{96-16\sqrt{21}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-96)+16\sqrt{21}}{2*-16}=\frac{96+16\sqrt{21}}{-32}
$